A) \[{{E}_{k}}\]
B) \[\frac{{{E}_{k}}}{2}\]
C) \[\frac{{{E}_{k}}}{\sqrt{2}}\]
D) zero
Correct Answer: B
Solution :
Key Idea: At the highest point vertical component of velocity is zero. Kinetic energy is possessed due to velocity. If m is mass of ball, then kinetic energy is \[{{E}_{k}}=\frac{1}{2}m{{u}^{2}}\] At the highest point or path only horizontal component of velocity exists, hence kinetic energy is, \[E{{}_{k}}=\frac{1}{2}m{{(u\cos 45{}^\circ )}^{2}}=\frac{1}{2}m{{\left( \frac{u}{\sqrt{2}} \right)}^{2}}\] \[\therefore \] \[E{{}_{k}}=\frac{1}{2}\left( \frac{1}{2}m{{u}^{2}} \right)=\frac{{{E}_{k}}}{2}\]You need to login to perform this action.
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