A) \[2.4\times {{10}^{-3}}\]
B) \[-2.4\times {{10}^{-3}}\]
C) \[4.2\times {{10}^{2}}\]
D) \[4.8\times {{10}^{-2}}\]
Correct Answer: C
Solution :
Given, \[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}K=2.4\times {{10}^{-3}}\] \[PC{{l}_{3}}+C{{l}_{2}}PC{{l}_{5}}\] \[K=?\] \[\therefore \]\[K=\frac{1}{K}=\frac{1}{2.4\times {{10}^{-3}}}=4.2\times {{10}^{2}}\]You need to login to perform this action.
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