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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2006

  • question_answer
        At a given temperature the equilibrium constant for the reaction of\[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}\]is\[2.4\times {{10}^{-3}}\]. At the same temperature, the equilibrium constant for the reaction\[PC{{l}_{3}}(g)+C{{l}_{2}}(g)PC{{l}_{5}}(g)\]is

    A)  \[2.4\times {{10}^{-3}}\]             

    B)  \[-2.4\times {{10}^{-3}}\]

    C)  \[4.2\times {{10}^{2}}\]                               

    D)  \[4.8\times {{10}^{-2}}\]

    Correct Answer: C

    Solution :

                    Given, \[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}K=2.4\times {{10}^{-3}}\] \[PC{{l}_{3}}+C{{l}_{2}}PC{{l}_{5}}\]         \[K=?\] \[\therefore \]\[K=\frac{1}{K}=\frac{1}{2.4\times {{10}^{-3}}}=4.2\times {{10}^{2}}\]


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