A) \[x=f(y)\]
B) \[f(1)=3\]
C) \[y\]increases with\[x\]for\[x<1\]
D) \[f\]is a rational function of\[x\]
Correct Answer: A
Solution :
Given, \[y=f(x)=\frac{x+2}{x-1}\] \[\therefore \]\[f(y)=f\left( \frac{x+2}{x-1} \right)=\frac{\frac{x+2}{x-1}+2}{\frac{x+2}{x-1}-1}\] \[f(y)=\frac{x+2+2x-2}{x+2-x+1}\] \[\Rightarrow \] \[f(y)=\frac{3x}{3}=x\] \[\therefore \] \[x=f(y)\]You need to login to perform this action.
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