A) \[P(B/A)=P(B)-P(A)\]
B) \[P(A\cup B)=P(A)+P(B)\]
C) \[P(A\cap B)=P(A)P(B)\]
D) none of the above
Correct Answer: D
Solution :
Given\[P(A\cup B)=P(A)+P(B)-P(A).P(B)\] ...(i) AIso \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\]...(ii) From Eqs. (i) and (ii)\[P(A\cap B)=P(A)P(B)\] \[\therefore \]A and B are independent events.You need to login to perform this action.
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