A) \[3y+x-8=0\]
B) \[3x+y+6=0\]
C) \[x+3y+14=0\]
D) none of these
Correct Answer: C
Solution :
Key Idea: Equation of line perpendicular to \[ax+by+c=0\]is\[bx-ay+\lambda =0.\] The equation of line perpendicular to line \[3x-y+5=0\] is\[-x-3y+\lambda =0\] ...(i) Also if passes through\[(-2,-4)\]. \[\Rightarrow \] \[+2+12+\lambda =0\] \[\Rightarrow \] \[\lambda =-14\] \[\therefore \]Required equation of line is \[-x-3y-14=0\] \[\Rightarrow \] \[x+3y+14=0\]. [from(i)]You need to login to perform this action.
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