JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2006

  • question_answer
        In the reaction sequence\[C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[(ii){{H}_{2}}O/Zn]{(i){{O}_{3}}}\Pr oducts\]Products will be

    A) \[C{{H}_{3}}COC{{H}_{3}}\]

    B) \[C{{H}_{3}}COC{{H}_{2}}OH\]

    C) \[C{{H}_{3}}COOH+HCOOH\]

    D) \[C{{H}_{3}}CHO+HCHO\]

    Correct Answer: D

    Solution :

                    Key Idea: The reaction is ozonolysis. During the reaction\[C=C\]breaks to give carbonyl compounds. \[C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[{{H}_{2}}O/2]{{{O}_{3}}}\underset{acetaldehyde}{\mathop{C{{H}_{3}}CHO}}\,+\underset{formaldehyde}{\mathop{HCHO}}\,\]


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