A) a function
B) transitive
C) not symmetric
D) reflexive
Correct Answer: C
Solution :
Let R = {(1, 3), (4, 2), (2, 4), (2,3), (3,1)} is a relation on the set\[A=\{1,\text{ }2,\text{ }3,\text{ }4\},\]then (a) Since\[(2,4)\in R\]and\[(2,3)\in R,\]so R is not a function. (b) Since\[(1,3)\in R\]and\[(3,1)\in R\]but\[(1,1)\cancel{\in }R\]. So R is not transitive. (c) Since\[(2,3)\in R\]but\[(3,2)\cancel{\in }R,\]so R is not symmetric. (d) Since\[(4,4)\cancel{\in }R,\]so R is not reflexive, Hence the option is correct.
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