A) 4L
B) 2L
C) L/2
D) L/4
Correct Answer: C
Solution :
In the condition of resonance \[{{X}_{L}}={{X}_{C}}\] Or \[\omega L=\frac{1}{\omega C}\] ?.(i) Since, resonant frequency remains unchanged, so, \[\sqrt{LC}=constant\] or \[LC=\]constant \[\therefore \] \[{{L}_{1}}{{C}_{1}}={{L}_{2}}{{C}_{2}}\] \[\Rightarrow \] \[L\times C={{L}_{2}}\times 2C\] \[\Rightarrow \] \[{{L}_{2}}=\frac{L}{2}\]You need to login to perform this action.
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