A) 540 nm
B) 400 nm
C) 310 nm
D) 220 nm
Correct Answer: C
Solution :
\[\frac{hc}{{{\lambda }_{0}}}=\phi \] \[\Rightarrow \]\[{{\lambda }_{\max }}=\frac{hc}{\phi }=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{4\times 1.6\times {{10}^{-19}}}\] \[=310\text{ }nm\]You need to login to perform this action.
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