A) \[\frac{3}{2}\]
B) \[\frac{5}{2}\]
C) \[\frac{7}{2}\]
D) \[\frac{9}{2}\]
Correct Answer: C
Solution :
The distance between \[4x+2y+4z-16=0\] and\[4x+2y+4z+5=0\]is\[\left| \frac{5+16}{\sqrt{16+4+16}} \right|\] \[=\left| \frac{21}{\sqrt{36}} \right|=\frac{21}{6}=\frac{7}{2}\]You need to login to perform this action.
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