A) One
B) Four
C) Two
D) Three
Correct Answer: D
Solution :
The force exerted by machine gun on mans hand in firing a bullet = change in momentum per second on a bullet or rate of change of momentum \[=\left( \frac{40}{1000} \right)\times 1200=48\,N\] The force exerted by man on machine gun= force exerted on man by machine gun = 144 N Hence, number of bullets fired\[=\frac{144}{48}=3\]You need to login to perform this action.
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