A) \[-2F\]
B) \[F/3\]
C) \[-2F/3\]
D) \[-F/3\]
Correct Answer: C
Solution :
Force acting between two current carrying conductors \[F=\frac{{{\mu }_{0}}}{2\pi }\frac{{{I}_{1}}{{I}_{2}}}{d}l\] ?(i) where\[d=\]distance between the conductors, \[l=\]length of each conductor. Again \[F=\frac{{{\mu }_{0}}}{2\pi }\frac{(-2{{I}_{1}})({{I}_{2}})}{(3d)}.l\] \[=-\frac{{{\mu }_{0}}}{2\pi }\frac{2{{I}_{1}}{{I}_{2}}}{3d}.l\] ...(ii) Thus, from Eqs. (i) and (ii) \[\frac{F}{F}=-\frac{2}{3}\] \[\Rightarrow \] \[F=-\frac{2}{3}F\]You need to login to perform this action.
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