A) \[0\]
B) \[1\]
C) \[\frac{1}{mn}\]
D) \[\frac{1}{m}+\frac{1}{n}\]
Correct Answer: A
Solution :
Given that, \[{{T}_{m}}=\frac{1}{n}\] \[\Rightarrow \] \[a+(m-1)d=\frac{1}{n}\] ...(i) and \[{{T}_{n}}=\frac{1}{m}\] \[\Rightarrow \] \[a+(n-1)d=\frac{1}{m}\] ...(ii) On solving Eqs. (i) and (ii), we get \[a=\frac{1}{mn}\]and \[d=\frac{1}{mn}\] So, \[a-d=\frac{1}{mn}-\frac{1}{mn}=0\]You need to login to perform this action.
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