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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2007

  • question_answer
        A machine gun fires a bullet of mass 40 g with velocity\[1200\text{ }m{{s}^{-1}}\]. The man holding it, can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?

    A)  One                                     

    B)  Four

    C)  Two                                     

    D)  Three

    Correct Answer: D

    Solution :

                    The force exerted by machine gun on mans hand in firing a bullet = change in momentum per second on a bullet or rate of change of momentum \[=\left( \frac{40}{1000} \right)\times 1200=48\,N\] The force exerted by man on machine gun= force exerted on man by machine gun = 144 N Hence, number of bullets fired\[=\frac{144}{48}=3\]


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