A) 1.68V
B) 1.40V
C) 0.91V
D) 0.63V
Correct Answer: C
Solution :
\[Sn(s)+2F{{e}^{3+}}(aq)\xrightarrow[{}]{{}}2F{{e}^{2+}}(aq)+S{{n}^{2+}}(aq)\] \[E_{cell}^{o}=E_{ox}^{o}+E_{red}^{o}\] \[=E_{Sn/S{{n}^{2+}}}^{o}+E_{F{{e}^{3}}/F{{e}^{2+}}}^{o}\] Given \[E_{S{{n}^{2+}}/Sn}^{o}=-0.14\] \[\therefore \] \[E_{Sn/S{{n}^{2+}}}^{o}=+0.14V\] \[E_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}=0.77V\] \[\therefore \] \[E_{cell}^{o}=0.14+0.77=0.91V\]You need to login to perform this action.
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