A) 10 mL
B) 20 mL
C) 40 mL
D) 60 mL
Correct Answer: C
Solution :
\[{{H}_{3}}P{{O}_{3}}\]is a dibasic acid (containing two ionisable protons attached to\[O\]directly). \[{{H}_{3}}P{{O}_{3}}2{{H}^{+}}+HPO_{4}^{2-}\] \[\therefore \]\[0.1\,M\,{{H}_{3}}P{{O}_{3}}=0.2\,N\,{{H}_{3}}P{{O}_{3}}\] and \[0.1\text{ }M\text{ }KOH=0.1\text{ }N\text{ }KOH\] \[\underset{(KOH)}{\mathop{{{N}_{1}}{{V}_{1}}}}\,=\underset{({{H}_{3}}P{{O}_{3}})}{\mathop{{{N}_{2}}{{V}_{2}}}}\,\] \[0.1{{V}_{1}}=0.2\times 20\] \[{{V}_{1}}=40\,mL\]
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