A) \[Cl\]
B) \[N{{H}_{2}}\]
C) \[O{{C}_{2}}{{H}_{5}}\]
D) \[OCOC{{H}_{3}}\]
Correct Answer: A
Solution :
\[C{{l}^{-}}\]is the best leaving group being the weakest nucleophile out of \[NH_{2}^{-},C{{l}^{-}},\overline{O}-{{C}_{2}}{{H}_{5}}\]and \[{{O}^{-}}-\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\] Note: If acid HX is weak, its conjugate base\[{{X}^{-}}\]is strong and vice-versa. \[N{{H}_{3}}<{{C}_{2}}{{H}_{5}}OH<C{{H}_{3}}COOH<-HCl\] Acidic strength increasing \[NH_{2}^{-}>{{C}_{2}}{{H}_{5}}{{O}^{-}}>C{{H}_{3}}CO{{O}^{-}}>C{{l}^{-}}\] Basic strength increasing conjugate baseYou need to login to perform this action.
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