2. Solved Papers
  3. JAMIA MILLIA ISLAMIA

JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2008

  • question_answer
        If\[A=\left[ \begin{matrix}    \cos \theta  & -\sin \theta   \\    \sin \theta  & \cos \theta   \\ \end{matrix} \right],\]then which of the following statement is not correct?

    A)  A is orthogonal matrix

    B) \[A\]is orthogonal matrix

    C)  Determinant\[A\equiv 1\]

    D)  A is not invertible

    Correct Answer: D

    Solution :

                    Given that, \[A=\left[ \begin{matrix}    \cos \theta  & -\sin \theta   \\    \sin \theta  & \cos \theta   \\ \end{matrix} \right]\] Now \[|A|={{\cos }^{2}}\theta +{{\sin }^{2}}\theta \ne 0,\] \[\therefore \]A is invertible.. Thus option  is not correct.


You need to login to perform this action.
You will be redirected in 3 sec spinner