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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2008

  • question_answer
        The equation of a simple harmonic wave is given by\[y=5\sin \frac{\pi }{2}(100t-x),\]where\[x\]and y are in metre and time is in second. The period of the wave in second will be

    A)  0.04                                      

    B)  0.01

    C)  1                                            

    D)  5

    Correct Answer: A

    Solution :

                    The given equation is \[y=5\sin \frac{\pi }{2}(100t-x)\]                      ...(i) Comparing Eq. (i) with standard wave equation, given by \[y=A\sin (\omega t-kx)\]                 ...(ii) we have                 \[\omega =\frac{100\pi }{2}=50\pi \] \[\Rightarrow \]               \[\frac{2\pi }{T}=50\pi \] \[\Rightarrow \]               \[T=\frac{2\pi }{50\pi }=0.04\,s\]


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