A) 392
B) 31.6
C) 278
D) 156
Correct Answer: A
Solution :
Mohrs salt is\[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}.FeS{{O}_{4}}.6{{H}_{2}}O\]The equation is \[5F{{e}^{2+}}+MnO_{4}^{-}+8{{H}^{+}}\xrightarrow[{}]{{}}\] \[2F{{e}^{3+}}+M{{n}^{2+}}+4{{H}_{2}}O\] Total change in oxidation number of iron \[=(+3)-(+2)\] \[=+1\] So, equivalent wt. of Mohrs salt \[=\frac{Mol.\text{ }wt.\text{ }of\text{ }Mohrs\text{ }salt}{1}\] \[=\frac{392}{1}\] \[=392\]You need to login to perform this action.
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