2. Solved Papers
  3. JAMIA MILLIA ISLAMIA

JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2008

  • question_answer
        For a reversible reaction: \[X(g)+3Y(g)2Z(g);\]\[\Delta H=-40\,kJ,\]the standard entropies of\[X,Y\]and Z are 60, 40 and  \[50~J{{K}^{-1}}mo{{l}^{-1}}\] respectively  The temperature at which the above reaction attains equilibrium is about

    A)  400 K                                   

    B)  500 K

    C)  273 K                                   

    D)  373 K

    Correct Answer: B

    Solution :

                    \[X(g)+3Y(g)2Z(g)\] \[\Delta S{}^\circ =2S{}^\circ (Z)-\{S{}^\circ (X)+3S{}^\circ (Y)\}\] \[=2\times 50-\{60+3\times 40\}\] \[=100-180=-80\,J{{K}^{-1}}mo{{l}^{-1}}\] Given \[\Delta H{}^\circ =-40\,kJ=-40,000J\]                 \[\Delta G{}^\circ =0\] At/equilibrium,                 \[\Delta G{}^\circ =0\] \[\therefore \]                  \[\Delta H{}^\circ =T\Delta S{}^\circ \] Or                           \[T=\frac{\Delta H{}^\circ }{\Delta S{}^\circ }=\frac{40,000}{80}=500K\]


You need to login to perform this action.
You will be redirected in 3 sec spinner