JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2009

  • question_answer
        The ratio of the adiabatic bulk modulus to the isothermal bulk modulus of a perfect gas is equal to (symbols have their usual meanings)

    A)  \[{{C}_{p}}-{{C}_{V}}\]                 

    B) \[\frac{{{C}_{P}}}{{{C}_{V}}}\]

    C)  \[\frac{{{C}_{V}}}{{{C}_{P}}}\]                                  

    D) \[\sqrt{\frac{{{C}_{P}}}{{{C}_{V}}}}\]

    Correct Answer: B

    Solution :

                    Adiabatic bulk modulus\[={{B}_{adia}}=\gamma P\] Isothermal bulk modulus\[={{B}_{iso}}=P\] \[\Rightarrow \]               \[\frac{{{B}_{adia}}}{{{B}_{iso}}}=\gamma =\frac{{{C}_{P}}}{{{C}_{V}}}\]


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