A) is change by about 16%
B) is halved
C) is changed by 26%
D) is unchanged
Correct Answer: C
Solution :
Partial pressure of a gas\[\alpha \]mole fraction mole fraction of\[{{O}_{2}}\]at start \[=\frac{3}{10}\times 100=30\] mole fraction of\[{{O}_{2}}\]at final stage \[=\left( \frac{3}{10}-\frac{2}{9} \right)\times 100=\frac{70}{9}=8\] % change\[=\frac{8}{30}\times 100\approx 26%\]You need to login to perform this action.
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