A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
\[Eq\,mass=\frac{Weighty(g)}{Number\text{ }of\text{ }equivalent}\] \[=\frac{0.45}{20\times 0.5\times {{10}^{-3}}}=45\] Basicity of the acid\[=\frac{Mol.\text{ }mass}{Eq.\,mass}=\frac{90}{45}=2\]You need to login to perform this action.
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