A) \[\frac{\pi }{3},\frac{\pi }{6}\]
B) \[\frac{\pi }{4},\frac{\pi }{4}\]
C) \[\frac{\pi }{8},\frac{3\pi }{8}\]
D) \[\frac{\pi }{12},\frac{5\pi }{12}\]
Correct Answer: C
Solution :
We have, AD = p and \[BC=2\sqrt{2}p\] Clearly, \[p=a\sin \theta =b\cos \theta \]You need to login to perform this action.
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