A) \[B{{r}^{-}}<F{{e}^{2+}}<Al\]
B) \[F{{e}^{2+}}<Al<B{{r}^{-}}\]
C) \[Al<B{{r}^{-}}<F{{e}^{2+}}\]
D) \[Al<F{{e}^{2+}}<B{{r}^{-}}\]
Correct Answer: A
Solution :
Reducing power ie, the tendency to lose electrons increases as the reduction potential decreases so the increasing order of reducing power of the given ions is\[B{{r}^{-}}~<F{{e}^{2+}}<Al\].You need to login to perform this action.
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