A) 50%
B) 72.24%
C) 55.3%
D) 43%
Correct Answer: B
Solution :
Percentage of ionic Character\[=16({{x}_{A}}-{{x}_{B}})+3.5{{({{x}_{A}}-{{x}_{B}})}^{2}}\] percentage ionic character \[=16(4-1.2)+3.5{{(4-1.2)}^{2}}\]\[=44.8+27.44=72.24\]You need to login to perform this action.
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