A) 360 N
B) 720 N
C) 180 N
D) \[120\times 10.8\text{ }N\]
Correct Answer: A
Solution :
\[v=u+at\] \[\therefore \] \[0=\left( 108\times \frac{5}{18} \right)+a\times 10\] \[\Rightarrow \] \[0=6\times 5+a\times 10\] \[\Rightarrow \] \[0=-\frac{30}{10}=-3\,m{{s}^{-2}}\] Hence, force required \[F=ma=120\times 3=360N\]You need to login to perform this action.
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