A) charge
B) resistance
C) voltage
D) current
Correct Answer: B
Solution :
\[X=\frac{{{\varepsilon }_{0}}lV}{t}\] \[=\frac{[{{M}^{-1}}{{L}^{-3}}+{{T}^{4}}{{A}^{2}}][L][M{{L}^{2}}{{T}^{-3}}{{A}^{-1}}]}{[T]}\] \[=[{{M}^{0}}{{L}^{0}}{{T}^{0}}A]\] Which represents electric current.You need to login to perform this action.
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