A) 0.1 m
B) 0.2 M
C) 0.3 M
D) 0.4 M
Correct Answer: A
Solution :
By law of conservation of energy, we have loss in gravitational potential energy = gain in elastic potential energy \[\Rightarrow \] \[mg(h+x)=\frac{1}{2}k{{x}^{2}}\] \[2\times 10(0.4+x)=\frac{1}{2}1960\times {{x}^{2}}\] \[\Rightarrow \] \[8+20x=980{{x}^{2}}\] \[\Rightarrow \] \[980{{x}^{2}}-20x-8=0\] Solving, we get \[x=0.1\text{ }m\]You need to login to perform this action.
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