A) isonitrile
B) nitrile
C) nitrite
D) oxime
Correct Answer: B
Solution :
\[\underset{Methyl\text{ }cyanide}{\mathop{C{{H}_{3}}-C\equiv N}}\,\xrightarrow[\begin{smallmatrix} Na-{{C}_{2}}{{H}_{5}}OH \\ or\,LiAl{{H}_{4}} \end{smallmatrix}]{Ni-{{H}_{2}}}\underset{Ethyl\text{ }amine}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\] \[C{{H}_{3}}-C\equiv N\xrightarrow[{}]{{{H}_{2}}O}C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-N{{H}_{2}}\] \[\xrightarrow{{{H}_{2}}O}C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-OH+N{{H}_{3}}\]You need to login to perform this action.
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