A) \[2:1\]
B) \[4:1\]
C) \[8:1\]
D) \[16:1\]
Correct Answer: D
Solution :
\[{{R}_{n}}\propto {{n}^{2}}\] \[\Rightarrow \] \[{{A}_{n}}\propto {{n}^{2}}\] Hence, \[\frac{{{A}_{2}}}{{{A}_{1}}}=\frac{n_{2}^{4}}{n_{1}^{4}}\] \[\Rightarrow \] \[\frac{{{A}_{2}}}{{{A}_{1}}}=\frac{{{(2)}^{4}}}{{{(1)}^{4}}}=\frac{16}{1}\]
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