A) \[2a\text{ }co{{t}^{2}}\alpha \]
B) \[4a\text{ }cose{{c}^{2}}\alpha \]
C) \[4a\text{ }cot\,\alpha \]
D) None of these
Correct Answer: B
Solution :
Let\[p(at_{1}^{2},2a{{t}_{1}})\]and \[Q(at_{2}^{2},2a{{t}_{2}})\]be the end points of the focal chord PQ of the parabola \[{{y}^{2}}=4ax\]and which makes an angle\[\alpha \]with the axis of parabola.You need to login to perform this action.
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