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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2010

  • question_answer
        A thin magnet is cut into two equal parts by cutting it parallel to its length. If the original time period of vibration is 4 s the time period of each part in the same field will be

    A)  \[4s\]                                  

    B)  \[2s\]

    C)  \[4\sqrt{2}s\]                                   

    D)  None of these

    Correct Answer: A

    Solution :

                    Pole strength of each pole is halved but length is same, so its magnetic moment becomes half. As mass of each part is halved, moment of inertia\[I\]is halved. As           \[T=2\pi \sqrt{\frac{I}{MB}}\] \[\therefore \]  \[T=\sqrt{\frac{I/2}{(M/2)B}}=T\] Hence, T remains the same is 4 s.


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