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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2010

  • question_answer
        The moment of magnet is\[0.1\text{ }A{{m}^{2}}\]and the force acting on each pole in a uniform magnetic field of 0.36 oersted is\[1.44\times {{10}^{-4}}N\]. The distance between the poles of magnet is

    A)  2.5 cm                                 

    B)  5.0 cm

    C)  1.25cm                                

    D)  1.17cm

    Correct Answer: A

    Solution :

                    Here, \[M=0.1\text{ }A{{m}^{2}},\] \[B=0.36\]forested\[=0.36\times {{10}^{-4}}J,\]                 \[F=1.44\times {{10}^{-4}}N\] As           \[F=mB\] \[\therefore \]  \[m=\frac{F}{B}=\frac{1.44\times {{10}^{-4}}}{0.36\times {{10}^{-4}}}=4\,Am\] As           \[M=m\times 2l\] \[\therefore \]  \[2l=\frac{M}{m}=\frac{0.1}{4}m=2.5\,m\]


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