A) \[2.4\times {{10}^{15}}Hz\]
B) \[2.4\times {{10}^{20}}Hz\]
C) \[1.24\times {{10}^{15}}Hz\]
D) \[1.24\times {{10}^{20}}Hz\]
Correct Answer: B
Solution :
\[\frac{hc}{\lambda }={{10}^{3}}\,eV\] ...(i) \[hv={{10}^{6}}\,eV\] ...(ii) Dividing Eq. (ii) by Eq. (i), we get \[v={{10}^{3}}\frac{c}{\lambda }\] \[=\frac{{{10}^{3}}\times 3\times {{10}^{8}}}{1.24\times {{10}^{-9}}}\] \[=2.4\times {{10}^{20}}Hz\]
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