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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2010

  • question_answer
        A bus starts moving with acceleration\[2\text{ }m/{{s}^{2}}\]. A cyclist 96 m behind the bus starts simultaneously towards the bus of 20 m/s. After what time will he be able to overtake the bus?

    A)  \[4s\]                                  

    B)  \[8s\]

    C)  \[12s\]                                

    D)  \[16s\]

    Correct Answer: B

    Solution :

                    Let the cyclist overtake the bus after time t. Then, \[20\times t=96+\frac{1}{2}\times 2\times {{t}^{2}}\] or       \[{{t}^{2}}-20t+96=0\] or       \[(t-12)(t-8)=0\] or       \[t=8\text{ }s\] and \[12s\] Thus, the cyclist will overtake the bus after 8 s.


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