A) \[2.5\times {{10}^{-4}}\Omega \]
B) \[1.25\times {{10}^{-3}}\Omega \]
C) \[0.05\,\Omega \]
D) \[2.5\,\Omega \]
Correct Answer: A
Solution :
\[S=\frac{{{I}_{g}}G}{I-{{I}_{g}}}=\frac{50\times {{10}^{-6}}\times 24}{5-50\times {{10}^{-6}}}\]\[=2.5\times {{10}^{-4}}\,\Omega \]
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