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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2010

  • question_answer
        A particle of mass\[m=5\]is moving with a uniform speed\[v=3\sqrt{2}\]in the XOY plane along the line\[y=x+4\]. The magnitude of the angular momentum of the particle about the origin is

    A)  7.5 unit               

    B)  60 unit

    C)  \[40\sqrt{2}\]unit          

    D)  zero

    Correct Answer: B

    Solution :

                    Angular momentum, \[J=mvr\] where, r is length of perpendicular drawn on line\[y=x+4\]from origin                 \[=\frac{0-0+4}{\sqrt{{{1}^{2}}+{{1}^{2}}}}=\frac{4}{\sqrt{2}}\] \[\therefore \]  \[J=5\times 3\sqrt{2}\frac{4}{\sqrt{2}}=60\,unit\]


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