A) \[{{K}_{p}}={{K}_{C}}\times RT\]
B) \[{{K}_{p}}={{K}_{C}}{{(RT)}^{2}}\]
C) \[{{K}_{p}}=\frac{{{K}_{C}}}{RT}\]
D) \[{{K}_{p}}=\frac{{{K}_{C}}}{{{(RT)}^{2}}}\]
Correct Answer: C
Solution :
\[{{K}_{p}}={{K}_{C}}{{(RT)}^{\Delta ng}}\] \[\Delta {{n}_{g}}=2-(2+1)=-1\] \[\therefore \] \[{{K}_{p}}={{K}_{C}}{{(RT)}^{-1}}\] \[{{K}_{p}}=\frac{{{K}_{C}}}{RT}\]You need to login to perform this action.
You will be redirected in
3 sec