A) \[4s\]
B) \[8s\]
C) \[12s\]
D) \[16s\]
Correct Answer: B
Solution :
Let the cyclist overtake the bus after time t. Then, \[20\times t=96+\frac{1}{2}\times 2\times {{t}^{2}}\] or \[{{t}^{2}}-20t+96=0\] or \[(t-12)(t-8)=0\] or \[t=8\text{ }s\] and \[12s\] Thus, the cyclist will overtake the bus after 8 s.You need to login to perform this action.
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