A) 0.0006
B) 0.46
C) 0.57
D) 0.83
Correct Answer: A
Solution :
\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\]\[=26{{(82.05\times 523)}^{-1}}\]\[=\frac{26}{82.05\times 523}=6.06\times {{10}^{-4}}atm\]You need to login to perform this action.
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