A) \[b<1\]
B) \[b\ge 1\]
C) \[b>1\]
D) \[b\le 1\]
Correct Answer: C
Solution :
Given, \[f(x)=\sin x-bx+c\] \[\Rightarrow \] \[f(x)=\cos x-b\] Since, it is decreasing, \[\therefore \] \[f(x)<0\] \[\Rightarrow \] \[\cos x<b\] \[\Rightarrow \] \[b>1\] \[(\because \cos x\le 1)\]You need to login to perform this action.
You will be redirected in
3 sec