A) \[x\]
B) \[a\]
C) \[2a+3x\]
D) \[d{{x}^{2}}\]
Correct Answer: D
Solution :
Applying\[{{R}_{3}}\to {{R}_{3}}-x{{R}_{2}}\]and \[{{R}_{2}}\to {{R}_{2}}-x{{R}_{1}}\] \[\therefore \] \[f(x)=\left| \begin{matrix} a & -1 & 0 \\ 0 & a+x & -1 \\ 0 & 0 & a+x \\ \end{matrix} \right|=a{{(a+x)}^{2}}\] \[\therefore \] \[f(2x)-f(x)=a[{{(a+2x)}^{2}}-{{(a+x)}^{2}}]\] \[=a(a+2x-a-x)(a+2x+a+x)\] \[=ax(2a+3x)\]You need to login to perform this action.
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