A) 2 and 9
B) 3 and 2
C) 2/3 and 9
D) 3/2 and 6
Correct Answer: C
Solution :
Given, \[{{T}_{1}}{{=}^{n}}{{C}_{0}}=1\] ?.(i) \[{{T}_{2}}{{=}^{n}}{{C}_{1}}ax=6x\] \[\Rightarrow \] \[nax=6x\] ...(ii) and \[{{T}_{3}}{{=}^{n}}{{C}_{2}}{{(ax)}^{2}}=16{{x}^{2}}\] \[\Rightarrow \] \[\frac{n(n-1)}{2}{{a}^{2}}{{x}^{2}}=16{{x}^{2}}\] ?.(iii) On solving Eqs. (ii) and (iii), we get \[a=\frac{2}{3}\]and \[n=9\]You need to login to perform this action.
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