A) 1
B) 2
C) \[\pi \]
D) \[2\pi \]
Correct Answer: B
Solution :
\[\therefore \]Required area\[=\int_{-\pi /2}^{\pi /2}{|\sin y|}\,dy\]
\[=2\int_{0}^{\pi /2}{\sin y\,dy}\] \[=2\]
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