JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        Two springs are made to oscillate simple harmonically due to the same mass individually. The time periods obtained are\[{{T}_{1}}\]and\[{{T}_{2}}\]. If both the springs are connected in series and then made to oscillate by the same mass, the resulting time will be

    A)  \[{{T}_{1}}+{{T}_{2}}\]                 

    B)  \[\frac{{{T}_{1}}{{T}_{2}}}{{{T}_{1}}+{{T}_{2}}}\]

    C)  \[\sqrt{T_{1}^{2}+T_{2}^{2}}\]                 

    D)  \[\frac{{{T}_{1}}+{{T}_{2}}}{2}\]

    Correct Answer: C

    Solution :

                    Let spring constants of two springs are\[{{k}_{1}}\]and \[{{k}_{2}}\]respectively, then \[{{T}_{1}}=2\pi \sqrt{\frac{m}{{{k}_{1}}}}\] and          \[{{T}_{2}}=2\pi \sqrt{\frac{m}{{{k}_{2}}}}\] \[\Rightarrow \]               \[{{k}_{1}}=\frac{4{{\pi }^{2}}m}{T_{1}^{2}}\] and        \[{{k}_{2}}=\frac{4{{\pi }^{2}}m}{T_{2}^{2}}\] When two springs are connected in series, then                 \[T=2\pi \sqrt{\frac{m}{{{k}_{eq}}}}\] where  \[{{k}_{eq}}=\frac{{{k}_{1}}{{k}_{2}}}{{{k}_{1}}+{{k}_{2}}}\] \[\Rightarrow \]               \[T=\sqrt{T_{1}^{2}+T_{2}^{2}}\]


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