A) 14
B) 12
C) 16
D) 10
Correct Answer: B
Solution :
The total fringe shift is \[H=\frac{\beta }{\lambda }(\mu -1)t\] The number of fringes that will shift \[=\frac{total\text{ }fringe\text{ }shift}{fringe\text{ }width}\] Or \[n=\frac{\frac{\beta }{\lambda }(\mu -1)t}{\beta }=\frac{(\mu -1)t}{\lambda }\] Or \[n=\frac{(1.4-1)\times 2.4\times {{10}^{-5}}}{800\times {{10}^{-9}}}\] Or \[n=\frac{0.4\times 2.4\times {{10}^{-5}}}{8\times {{10}^{-7}}}\] Or \[n=12\]You need to login to perform this action.
You will be redirected in
3 sec