A) \[0.125\,\Omega \]
B) \[2\,\Omega \]
C) \[3\,\Omega \]
D) for finding the value of\[X,\]the emf of cell is required
Correct Answer: A
Solution :
If is a balanced Wheatstone bridge Hence, \[\frac{P}{R}=\frac{Q}{X}\] Here, \[P=12+4=16\,\Omega \] \[Q=1+3=4\,\Omega \] \[R=\frac{1}{2}\,\Omega \] So, \[\frac{16}{0.5}=\frac{4}{X}\] \[X=0.125\,\Omega \]You need to login to perform this action.
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